Let $l_h,l_j$ be the leap lengths of the hare & jackal respectively. Let $r_h, r_j$ be the number of leaps per second (rate).
We have $3 l_h = 4 l_j$, or $\frac{l_h}{l_j} = \frac{4}{3}$.
We also have $r_h = \frac{6}{5} r_j$, or $\frac{r_h}{r_j} = \frac{6}{5}$.
Their speeds are given by the leap rate times the leap length, so $\frac{s_h}{s_j} = \frac{l_h r_h}{l_j r_j}= \frac{l_h}{l_j} \frac{r_h}{r_j} = \frac{4}{3} \frac{6}{5} = \frac{8}{5}$.