In general, try to get some function of $x$ and $y$ equal to two different constants. Then set that function equal to $u$. Then try to find another function of $x$ and $y$ equal to two different constants and set that equal to $v$.
So your first two equations hand you $x^2+y^2 = u$ on a silver platter. The second two equations can be rewritten
$$\frac{y}{x} = 3, \frac{y}{x}=4.$$
So set $v=\frac{y}{x}.$