The chance you get a match on day $1$ is $\frac 1n$. Imagine you pull from the left first, then there are $n$ socks in the right drawer to choose from and $1$ matches.
The chance for any day is also $\frac 1n$. Imagine lining up all the socks in the order you will pull them. For a given day $k$, imagine swapping the first and $k$th stocks in both rows. Now day $k$ is a match if and only if the first day would have been a match before the swap. It is just confusing yourself to worry about whether day $1$ matched before you draw day $k$. You can do that, but it will still come out $\frac 1n$.