No it is not correct, just consider $A=\left[\begin{matrix} 2 & 0 \\\ 0 & 1\end{matrix} \right]$ and the two canonical basis vectors.
No it is not correct, just consider $A=\left[\begin{matrix} 2 & 0 \\\ 0 & 1\end{matrix} \right]$ and the two canonical basis vectors.