No. There are C$^*$-algebras that are not contained in any nuclear C$^*$-algebra. Any non-exact algebra would give the counterexample, as exactness passes to subalgebras.
No. There are C$^*$-algebras that are not contained in any nuclear C$^*$-algebra. Any non-exact algebra would give the counterexample, as exactness passes to subalgebras.