Actually, they're not.
Based on the Wikipedia article you linked, it looks like the polynomials in question are functions from $\mathbb{R}$ to $\mathbb{R}$. Such a function $f$ is computable if there is an oracle Turing machine that, when given $x \in \mathbb{R}$ as an oracle and $n$ as an input, produces the $n$-th digit of $f(x)$. Caveat: this definition is only essentially correct.
So if a polynomial has a non-computable real number as a coefficient, then it might not be a computable function. For example let $K$ be the real number corresponding to the halting set, so the $n$-th binary digit of $K$ is $1$ iff the $n$-th machine halts. Then the constant function $f(x)=K$ is not computable but is certainly a polynomial.
But if the polynomial has, for example, rational coefficients, then it is computable.