For each digit, you have either the digit itself, or the corresponding word. Each letter of the word can be upper or lower case, so in total there are $1 + 2^l$ possibilities for a given digit, where $l$ is the number of letters in the word.
Thus, the number of possibilities for $123456789$ is $$(1+2^3)(1+2^3)(1+2^5)\cdots(1+2^4) = 128,711,132,649.$$
I have discounted far-fetched interpretations such as "444" for "three four", since this is ungrammatical. The one exception would be "2" for "one two", as the singular here is grammatical.