Vacuous, I'm not sure. But the answer, of course, is no. Even if your set $S$ is a closed interval in $\Bbb R$, consider $f_n(x)=nx$.
Vacuous, I'm not sure. But the answer, of course, is no. Even if your set $S$ is a closed interval in $\Bbb R$, consider $f_n(x)=nx$.