Let $X=C\bigl([0,1]\bigr)$ and $Y=\\{f\in F\mid f\text{ is differentiable and }f(0)=0\\}$. Then$$\begin{array}{rccc}D\colon&Y&\longrightarrow&X\\\&f&\mapsto&f'\end{array}$$is a vector space isomorphism. However, $X$ is complete, whereas $Y$ isn't (in both cases, with respect to the $\sup$-norm).