In general:
$$\log(a b) = \log(b) + \log(b)$$ So in your case: $$\log(EPX) =\log(E)+\log(P)+\log(X)$$ Which your textbook wrote as: $$e+p+x$$
In general:
$$\log(a b) = \log(b) + \log(b)$$ So in your case: $$\log(EPX) =\log(E)+\log(P)+\log(X)$$ Which your textbook wrote as: $$e+p+x$$