Find Probabilty of ~Fever I have been given this P(Strep(some infection)) = 0.15 P(fever|strep) = 0.6 P(fever|~strep) = 0.3 Find P(strep|fever) I could find this put by using bases rule. Bayes rule is `P(A/B) = P(B/A)*P(A) / P(B)` Here B is fever. How do I find P(fever)? Is it sum of `P(fever|strep) and this P(fever|~strep)` If I can do this, and find P(~fever), I get it more than 1. Where am I wrong? Thank you

It is found as follows:

$$ P(\text{fever}) = P(\text{fever} \mid \text{strep}) P(\text{strep}) \+ P(\text{fever} \mid \
eg\text{strep}) P(\
eg\text{strep}) $$

where $\
eg$ is the negation operator (I'm assuming that's what $\sim$ is in your question).