Kinematics initial velocity A grape is tossed straight up in the air and caught in the mouth. if the mouth is 1 foot higher than the point where the grape is released in the grape enters the mouth at 25 ft./s what was the initial velocity of the tossed grape

$v_f^2=v_o^2+2g\Delta x$

You have your final velocity, $v_f$. You also have a value for $\Delta x$, as you know the grape travels $1$ foot up. Finally, $g=32 ft/s^2$ at the surface of Earth. Can you proceed?