We know that two operational symbols have to exist in the red places : $$2\color{red}{\circ}\circ\color{red}{\circ}\circ=2015.$$ Then, we have $$\text{LHS}\le 2\times 9\times 9=162\lt 2015.$$
We know that two operational symbols have to exist in the red places : $$2\color{red}{\circ}\circ\color{red}{\circ}\circ=2015.$$ Then, we have $$\text{LHS}\le 2\times 9\times 9=162\lt 2015.$$