The next two paragraph give a proof of Corollary 24. The content of this proof is that if there are no inaccessible cardinals then we are done; otherwise there is a least inaccessible $\lambda$, in which case Lemma 25 proves that $\langle V_\lambda,\overline\in\rangle$ is a model of ZF+"There are no inaccessible cardinals".
In either case we see that the proof actually proves:
> $CON(\mathrm{ZF})\
rightarrow CON(\mathrm{ZF}+\exists\text{ a strongly inaccessible cardinal})$
Which also fits the two-liner proof based on Godel's incompleteness theorem which is given right after Corollary 24.