Dynamical system with no point of period 3 This is a repost of < I posted an answer to that question. Someone voted that answer down so that the Community bot would delete the question from the site. I feel that my answer contributed something worthwhile to the site, so I'm reposting the question, and posting my answer. Let $f:{\bf R}\to{\bf R}$ be strictly decreasing. How can we prove that there is no point of (minimal) period 3?

You can prove it by first establishing

1. if $f$ is strictly decreasing, then so is its third iterate,

2. If $f$ is strictly decreasing, it has exactly one fixed point, and

3. if $x$ is a fixed point of $f$, then it's a fixed point of the third iterate of $f$.