To show infimum of set is 0 I have read Archimedean property. > The exercise has question to find the infimum of set $A = \\{1/n: n \in \mathbb N\\}$. Intuitively I see infimum to be $0$. But I need hint to prove this using Archimedean property. Thanks.

Let $\epsilon >0$ For the Archimedean property, there exist $N \in \mathbb{N}$, such that $N\epsilon>1 $, so $\frac{1}{N}< \epsilon$