I figured out why the answer could be $\int_0^\pi2\pi x\sin x\,dx=2\pi^2$. The flying saucer can be visualized by looking at the following longitudinal section: ![Longitudinal section of flying saucer]( By using cylindrical shells, we have $V=\int_a^b2\pi xh\,dx$, where $a=0$, $b=\pi$ and $h=\sin x$. This leads us to the answer in the key $\int_0^\pi2\pi x\sin x\,dx=2\pi\cdot\pi=2\pi^2$.