No. See, for example, this answer for a simple example (in which $Y$ and $Z$ also are independent), that is, $X, Y, Z$ are _pairwise_ independent but not mutually independent, and so $X$ is not independent of the bivariate random variable $(Y,Z)$.
No. See, for example, this answer for a simple example (in which $Y$ and $Z$ also are independent), that is, $X, Y, Z$ are _pairwise_ independent but not mutually independent, and so $X$ is not independent of the bivariate random variable $(Y,Z)$.