How do I rationalize the equation $\frac{3-x}{1- \sqrt{x-2}}$? How do I rationalize this equation $$\frac{3-x}{1- \sqrt{x-2}} ? $$

$$\frac{3-x}{1-\sqrt{x-2}}=\frac{3-x}{1-\sqrt{x-2}}\frac{1+\sqrt{x-2}}{1+\sqrt{x-2}}=\frac{(3-x)(1+\sqrt{x-2})}{1-(x-2)}=$$

$$=\frac{(3-x)(1+\sqrt{x-2})}{3-x}=1+\sqrt{x-2}$$