There is a second scale involved that is established by the magnitudes of the initial conditions. $y_1(0)$ is small against $y_2(0)$ and by the second equation that stays that way for some time. So in first order one can consider $y_2$ constant.
Then apply the usual substitution for Riccati equations $y_1=-\frac{u'}{2u}$ to obtain $$u''+2ϵy_2u=0$$ to get a harmonic oscillator with frequency $\omega=\sqrt{2ϵy_2}$ which for the given data is $\sqrt2\cdot 0.16=0.22627$. The fraction $u'/u$ oscillates twice in every period of $u$ which gives a period for $y_1$ of $\pi/ω=13.8840$ which coincides with the period you can read off of your graph.