You are given $$I = \int {\frac{{dx}}{{{{\left( {{e^x} + 1} \right)}^2}}}} $$
Let $e^x+1=u$. Then, what does you integral become?
**SPOILER** You should get
> $I = \displaystyle \int {\frac{{du}}{{{u^2}\left( {u - 1} \right)}}}$
Then use partial fraction decomposition.