If you have not seen integration by parts before, it is strongly related to the product rule of differentiation. $$\frac{d}{dx}x^ne^{-x}=nx^{n-1}e^{-x}-x^ne^{-x}\\\ \left.x^ne^{-x}\right|_0^{\infty}=\int_0^{\infty}nx^{n-1}e^{-x}dx-\int_0^{\infty}x^ne^{-x}dx\\\ \int_0^{\infty}x^ne^{-x}dx=n\int_0^{\infty}x^{n-1}e^{-x}dx$$ So the integral with $n$ is related to the integral with $n-1$; and by the same rule that $n!$ is.