There are no others. Here's a proof using well-known facts about the cohomology of finite groups.
Let $G$ be a nontrivial finite group, and let $p$ be a prime dividing the order of $G$. Then there is a finite dimensional (and hence finite) $\mathbb{F}_pG$-module $M$ with $H^2(G,M)\
eq0$. A nonzero cohomology class represents a non-split extension $1\to M\to\tilde{G}\to G\to1$.
If the existence of $M$ is not familiar, but you believe that $H^k(G,\mathbb{F}_p)\
eq0$ for some $k>0$, then you can produce $M$ from the trivial $\mathbb{F}_pG$-module $\mathbb{F}_p$ by dimension shifting. Or for a specific $M$, take an exact sequence $$0\to M\to P_1\to P_0\to\mathbb{F}_p\to0,$$ where $P_1\to P_0\to\mathbb{F}_p\to0$ is a projective presentation of the trivial $\mathbb{F}_pG$-module.