Prove that triangles $SBX,PCY,RAQ,ABC$ have the same area > $ABC$ is a rt. angled triangle rt. angled at $A$. $ACPQ, BCYX, ABSR$ are squares drawn on $AC, BC , AB$ respectively. Prove that triangles $SBX,PCY,RAQ,ABC$ have the same area. ![enter image description here]( No clue except area of $ACY=1/2 .ACYL$ Please help.

Triangle $AQR$ is congruent to $ABC$.

Triangles $CPL$ and $BSJ$ in picture below are also congruent to $ABC$. But triangle $BXS$ has the same base $BX\cong BJ$ and the same altitude $SK$ as triangle $BSJ$, and triangle $PCY$ has the same base $CY\cong CL$ and the same altitude $PH$ as triangle $CPL$. Both $BXS$ and $PCY$ have then the same area as $ABC$.

![enter image description here](