Partial Fraction Using Heaviside cover-up method How to convert this equation into Partial fraction Using Heaviside Cover-up Method $$\frac{x^2}{(x+2)(2x+3)}$$ After trying to solve this I am ending up getting this which is incorrect : $$-\frac{4}{(x+2)}+\frac{9}{2(2x+3)}$$ Or is there any other way to get through. refernce to the method :- < <

As the power of $x$ is same in the numerator & the denominator

express it as $$A+\frac B{x+2}+\frac C{2x+3}$$ where $A,B,C$ are arbitrary constants

Then multiply out either sides by $(x+2)(2x+3)$ and compare the constants and the coefficients of $x,x^2$ to determine $A,B,C$

Clearly, $\displaystyle A=\frac1{2}$