Probability help! Am i wrong? So here is the summary for the question: 100 women use a new pregnancy test, 44 of the women are actually pregnant. Of the women who are pregnant, 35 test positive. Of the women who are not pregnant, 8 of them test positive. Calculate the probability for each event. Did I get this question right? Here is the question: A randomly selected test is negative, given the woman is not pregnant. I got: $P(\text{Negative|Not Pregnant}) = \frac{56}{66} = 0.85$ Is this correct?

You have enough data to make a complete cross-tabulation:

$$\begin{array}{r|c|c|c} &\text{pos.}&\text{neg.}&\text{total}\\\ \hline \text{pregnant}&35&9&44\\\ \hline \text{not pregnant}&8&48&56\\\ \hline \text{total}&43&57&100 \end{array}$$

There are $56$ women who are not pregnant, and $48$ of them test negative, so the probability that a randomly chosen non-pregnant woman tests negative is

$$\frac{48}{56}=\frac67=0.\overline{857142}\;.$$

This is slightly larger than your $\frac{56}{66}=\frac{28}{33}=0.\overline{84}$.