For $\vec F=-\hat x \frac {y}{x^2+y^2} +\hat y \frac{x}{x^2+y^2}$, we see that
$$|\vec F|=\frac1r$$
where $r=\sqrt{x^2+y^2}$ is the polar coordinate for the magnitude of the position vector $\vec r=\hat r r$.
Moreover, the direction of $\vec v$ is the polar unit vector $\hat \theta$ and is perpendicular to the position vector.
Hence, $\vec F$ rotates (circulates) around the origin counterclockwise and its "strength" increases as we move closer to the origin.
A point of interest is that while $\
abla \times \vec F=0$ for all $\vec r\
e0$, the line integral of $\vec F$ is not $0$ for any (smooth) contour that encircles the origin.