Of course this is possible. Choose a bijection $b: \mathbb R^n \to \mathbb R$ and define $\lambda \cdot v = b^{-1}(\lambda b(v))$ and $v+w=b^{-1}(b(v)+b(w))$.
Of course this is possible. Choose a bijection $b: \mathbb R^n \to \mathbb R$ and define $\lambda \cdot v = b^{-1}(\lambda b(v))$ and $v+w=b^{-1}(b(v)+b(w))$.