The line $x-1=y-1=z-1$ is the same as $x=y=z$ so it's all the points $(t,t,t)$, $t$ real. The plane perpendicular to this line at $(t,t,t)$ is $$x+y+z=3t$$ The points in this plane at distance 4 from $(t,t,t)$ also satisfy $$(x-t)^2+(y-t)^2+(z-t)^2=16$$ Solve the first equation for $t$ in terms of $x,y,z$, then put that in the second equation, and you should have an equation for the tube.