Assuming $\psi$ is not combinatorial, no, never, because subdivision preserves the homeomorphism type of the link of a vertex. (In particular, if it's not a sphere, you're out of luck.) This is reasonably straightforward to prove.
Assuming $\psi$ is not combinatorial, no, never, because subdivision preserves the homeomorphism type of the link of a vertex. (In particular, if it's not a sphere, you're out of luck.) This is reasonably straightforward to prove.