Probability of at least a woman or at least a right-handed person There are 10 people, 4 women and 6 men. Among the men, 3 are left-handed and among the women 2 are left-handed writers. Two people are chosen without replacement. Calculate the probability that the sample contains at least a right-handed person or at least one woman. I'm trying to solve the following question but I really don't know how to start it! Can someone help me? I believe I need to use combinations as I can choose a right-handed person in the first or second draw (the same for the woman) but I'm stuck in how to compute it. I know that the asked probability is P $=\frac{14}{15} $

**Hint:** A sample that does not contain "at least one right-handed person or at least one woman" consists only of left-handed men.