You need to find $x$ such that $P(X\le x)=0.15$. Since $0.15<0.5$, we will take the upper $0.15$ instead. You have that \begin{align}0.15=P(X\le x)=P\left(Z\le \frac{x-9.5}{0.4}\right)=\Phi\left(\frac{x-9.5}{0.4}\right)=1-\Phi\left(\frac{9.5-x}{0.4}\right)\end{align} Hence, from the standardized normal distribution table, you find that $$\Phi(1.03643)=0.85$$ So, you need to solve $1.03643=\frac{9.5-x}{0.4}$.