Since you're forming a six-person delegation, the only way both sides will be equal is if there are $3$ Adorians and $3$ Tellarites. (Repetition isn't appropriate here because one person can't be on the delegation twice).
Number of ways to choose $3$ Adorians = $\binom{10}{3}$.
Number of ways to choose $3$ Tellarites = $\binom{15}{3}$.
Since these are independent options, we multiply them together to get
$$\binom{10}{3}\binom{15}{3}$$