Can anyone help me for this first degree floor function equation? Find $y$ such that $$\lfloor y \rfloor + \lfloor 3y \rfloor = 5$$ First, I use the properties that $$n \leq y <n+1$$ And suppose $$\lfloor y\rfloor = 5-n$$ and $$\lfloor 3y\rfloor = n$$ But I’m stuck, could anyone help me?

Hint: write y as $n+d$ .Now the first term turns out to be n and for second term take cases for $0