calculate distance from centre I have the following question: ![enter image description here]( And i am asked to calculate the distance, d,. However, i am unsure how to do this. I know that in order for the see-saw to be in equilibrium then both sides should have equal weights.

HINT:

You have to balance out the turning force on both sides.

$1 \times 400 = 0.5 \times 200 + d \times 250.$

Solve for $d$.