since, $$speed = \frac{distance}{time}$$ $$x+y = \frac{8km}{4/6hr}$$ and $$x-y = \frac{8km}{1hr}$$ then solve both the equations.
since, $$speed = \frac{distance}{time}$$ $$x+y = \frac{8km}{4/6hr}$$ and $$x-y = \frac{8km}{1hr}$$ then solve both the equations.