With $n$ labelled vertices, there are $\dfrac{n(n-1)}{2}$ potential edges, each one of which may be present or not, so there are $2^{n(n-1)/2}$ possible different graphs.
With $n$ labelled vertices, there are $\dfrac{n(n-1)}{2}$ potential edges, each one of which may be present or not, so there are $2^{n(n-1)/2}$ possible different graphs.