Jug $B$ has $\frac{8}{11}-\frac37=\frac{23}{77}$ more water. Now take $\frac{23}{77}$ of water out of $B$ and pour in a jug $C$. Now both $A$ and $B$ have the same amount of water. Next pour half of $C$ in $B$ and the second half in $A$. This half is $\frac{23}{77}\times \frac12$.