The first two sentences, with proper parenthesization, do the job.
The third item is not right. There are as usual many equivalent options. Something like this would work: $$\lnot \exists x(\text{Car}(x) \land \text{Has}(\text{Batman},x)) \longrightarrow \text{Slow}(\text{Batman}).$$ Equivalently, we could use $$\forall x(\lnot\text{Car}(x) \lor \lnot\text{Has}(\text{Batman},x)) \longrightarrow \text{Slow}(\text{Batman}).$$ Somewhat simpler is the equivalent $$\exists x(\text{Car}(x) \land \text{Has}(\text{Batman},x)) \lor \text{Slow}(\text{Batman}).$$
The problem with your version is that it says, among other things, that unless Batman has my car, he is slow.
For the last, if there were a constant symbol Batmobile, one could do it. As it is, one really cannot, we cannot assume that Batman has a car called the Batmobile. And even if we take it for granted that he does, the fact that rich boy Batman has a fast car doesn't imply the Batmobile is fast.