Consider $$ A = \begin{pmatrix} 0 & 1 \\\ 0 & 0 \end{pmatrix} $$ As $\chi_A(t) = t^2$, $0$ has algebraic multiplicity $2$, but geometric multiplicity $1$.
Consider $$ A = \begin{pmatrix} 0 & 1 \\\ 0 & 0 \end{pmatrix} $$ As $\chi_A(t) = t^2$, $0$ has algebraic multiplicity $2$, but geometric multiplicity $1$.