Suppose you assume that you can write $\sqrt{6-2\sqrt5} = \sqrt a - \sqrt b$ for some rational numbers $a$ and $b$. Squaring both sides will give you $6-2\sqrt5 = a+b-2\sqrt{ab}$, and so \begin{align*} 6 &= a+b \\\ \sqrt{5} &= \sqrt{ab} \end{align*} So we want $ab=5$ and $a+b=6$. An obvious solution is, indeed, $a=5$ and $b=1$. (Taking $a=1$ and $b=5$ gives a negative result for $\sqrt a-\sqrt b$.)