Yes.
Your sphere is of the form $x^2+y^2+z^2=r$, now after shearing the quadratic form $x^2+y^2+z^2$ you will still have a quadratic form and it will still be positively definite (obviously).
Now for any positive definite form you can identify eigenvectors (which will become axes of the ellipse). Changing to the basis of eigenvectors the form will take the form $\alpha u^2+\beta v^2+\gamma w^2$ and the equation of the sheared sphere will take the form of an ellipsoid $\alpha u^2+\beta v^2+\gamma w^2=r$.