What happens when $f(t)=rect(\frac{x-10}{2})rect(\frac{x}{2}) $ ? Which takes priority?
> What happens when $f(t)=rect(\frac{x-10}{2})rect(\frac{x}{2}) $ ? Which takes priority?
The first function occurs between $9<x<11$ while the second rect occurs when $-1<x<1$. What exactly happens in this function?
EDIT:
Rect is defined as:
$$-\frac12<x<\frac12: 1 $$ $$else: 0$$
Just multiply point by point. You will see that $f(x)=0$.