Ah, don't worry, I forgot about the fact that $S_0(x) - S_0(x-1) = \frac{1}{[x]}$ and so we just use the summatary characterisation.
Ah, don't worry, I forgot about the fact that $S_0(x) - S_0(x-1) = \frac{1}{[x]}$ and so we just use the summatary characterisation.