You can have corners in continuous functions, and the absolute value function is a good example. Clearly there is not problem except at $x=0$. For $x=0$ you can do an $\epsilon - \delta$ proof taking $\delta=\epsilon$ and show continuity.
You can have corners in continuous functions, and the absolute value function is a good example. Clearly there is not problem except at $x=0$. For $x=0$ you can do an $\epsilon - \delta$ proof taking $\delta=\epsilon$ and show continuity.