There is no function satisfying the first and third conditions simultaneously. If a function satisfies the first condition, then there exists $A>0$ such that $|f(x)+k|
Note that this proof doesn't require $f$ to be increasing or even continuous.
There is no function satisfying the first and third conditions simultaneously. If a function satisfies the first condition, then there exists $A>0$ such that $|f(x)+k|
Note that this proof doesn't require $f$ to be increasing or even continuous.