we have $$y=\frac{x}{1-x}$$ ,multiplying by $1-x$ we get $$y-yx=x$$ adding $$yx$$ and we have $$y=x(1+y)$$ dividing by $$1+y\
e 0$$ we obtain $$x=\frac{y}{1+y}$$
we have $$y=\frac{x}{1-x}$$ ,multiplying by $1-x$ we get $$y-yx=x$$ adding $$yx$$ and we have $$y=x(1+y)$$ dividing by $$1+y\
e 0$$ we obtain $$x=\frac{y}{1+y}$$