Processing bash variable with sed bash variable LATLNG contains a latitude & longitude value in brackets like so `(53.3096,-6.28396)` I want to parse these into a variable called LAT and LON which I'm trying to do ...--prophetes.ai

Processing bash variable with sed bash variable LATLNG contains a latitude & longitude value in brackets like so `(53.3096,-6.28396)` I want to parse these into a variable called LAT and LON which I'm trying to do via sed like so `LAT=$(sed "s/($.$,$.$)/\1/g" "$LATLNG")` `LON=$(sed "s/($.$,$.$)/\2/g" "$LATLNG")` However, I get the following error: `sed: can't read (53.3096,-6.28396): No such file or directory`

This can be solved via pure shell syntax. It does require a temp variable because of the parentheses (brackets) though:

#!/bin/bash

LATLNG="(53.3096,-6.28396)"

tmp=${LATLNG//[()]/}
LAT=${tmp%,*}
LNG=${tmp#*,}

Alternatively, you can do it in one go by playing with `IFS` and using the `read` builtin:

#!/bin/bash

LATLNG="(53.3096,-6.28396)"

IFS='( ,)' read _ LAT LNG _ <<<"$LATLNG"