Let $B'=B\setminus A$. If $B'$ is finite, then biject $B$ with $A\cap B$, and use that bijection to biject $A\cup B = A\amalg B'$ with $A$ (where $\amalg$ denotes a disjoint union).
If $B'$ is infinite, let $D$ be a denumerable subset of $A$. Then biject $D\amalg B'$ with $D$, and use that bijection to get a bijection of $A\cup B = A\amalg B'$ with $A$.
(This requires you to prove that the union of two disjoint denumerable sets is denumerable; I trust you know how to do that)