To do this you want to look at what happens to points a little to the right, and a little to the left of $0$. So let $\epsilon >0$ be given and consider
(a) $f(\epsilon)=\epsilon-\epsilon^2<\epsilon$ so the points a little to the right are being drawn _towards_ $0$. Similarly a point $-\epsilon$ (slightly to the left of $0$) gets mapped to $f(-\epsilon)-\epsilon -\epsilon^2<-\epsilon$ are being forced _away_ from $0$, so it does half attracting, half repelling.
(b) We do the same procedure getting $f(\epsilon)=\epsilon+\epsilon^3>\epsilon$ and $f(-\epsilon) = -\epsilon -\epsilon^3<-\epsilon$ both push away from $0$ which makes it a repelling fixed point.
You should try (c) and (d) for yourself using an appropriate polynomial approximation for $\tan x$ in (d). $\tan x\approx x+{x^3\over 3}$ is good enough, for example.